Question 3

Question - 03 

The program will receive 3 English words inputs from STDIN. 

These three words will be read one at a time, in three separate line. 

The first word should be changed like all vowels should be replaced by $. 

The second word should be changed like all consonants should be replaced 

by #. 

The third word should be changed like all char should be converted to 

upper case. 

Then concatenate the three words and print them. 

Other than these concatenated word, no other characters/string should or 

message should be written to STDOUT. 

For example if you input how are you then output should be h$wa#eYOU. 

You can assume that input of each word will not exceed more than 5 chars.

#include <stdio.h>

#include <malloc.h>

#include <string.h>

int main() 

{ 

char *str1 = malloc(sizeof(char) * 256); 

char *str2 = malloc(sizeof(char) * 256); 

char *str3 = malloc(sizeof(char) * 256); 

scanf("%s %s %s", str1, str2, str3); 

int s1 = strlen(str1); 

int s2 = strlen(str2); 

int s3 =strlen(str3); 

for(int i = 0; i < s1; i++) 

 { 

 if(str1[i]=='a' || str1[i]=='e' || str1[i]=='i' || 

str1[i]=='o' || str1[i]=='u' || 

 str1[i]=='A' || str1[i]=='E' || str1[i]=='I' || 

str1[i]=='O' || str1[i]=='U') 

 str1[i] = '$'; 

 } 

for(int i = 0; i < s2; i++) 

 { 

 if(str2[i]!='a' && str2[i]!='e' && str2[i]!='i' && 

str2[i]!='o' && str2[i]!='u' && 

 str2[i]!='A' && str2[i]!='E' && str2[i]!='I' && 

str2[i]!='O' && str2[i]!='U') 

 str2[i] ='#'; 

 } 

for(int i = 0; i < s3; i++) 

 { 

 if(str3[i] >= 'a' && str3[i] <= 'z') 

 str3[i] = str3[i] - 32; 

 } 

printf("%s%s%s", str1, str2, str3); 

return 0; 

}